WebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer. Question: 9.2.1: Computing using modular arithmetic. Compute the value of the following expressions: (a) 4630 mod 9 (b) 387 mod 3 (c) [72 · (−65) + 211] mod 7 (d) [77 · (−65) + 147] mod 7 (e) 4412 mod 6 ... WebModulo Method. First need to divide the Dividend by the Divisor: 14 7 = 2.00. Next we take the Whole part of the Quotient (2) and multiply that by the Divisor (7): 2 x 7 = 14. And …
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WebCompute the value for each of the following expressions. (a) 215 div 7 (b) 215 mod 7 (c) (-215) div 7 (d) (-215) mod 7 (e) (77.(-65) + 147) mod 7 . Show transcribed image text. Expert Answer. Who are the experts? Experts are tested by Chegg as specialists in their subject area. We reviewed their content and use your feedback to keep the quality ... WebFeb 7, 2024 · That’s simple, Divide the two numbers ( eg. 7/3 = 2.333333) eliminate the decimal part (i.e., make the 2.33333 → 2) ( If there is no decimal part, the MOD value is 0, eg. multiply the divisor with the number you just found out ( 3 * 2 = 6) now subtract the result from the dividend (7 – 6 = 1, which is your MOD value) jody long whotv husband
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WebThis tells us how to find 10 n mod 7. For example, if I want 10 73 mod 7. 10 73 = 10 72 + 1 = 10 72 10 = ( 10 6) 12 10 = 10 mod 7 = 3. In general when calculating a n mod p where p is a prime, we cast off multiples of p − 1 from n i.e. a … WebHere we will list all the Factors of 14, 47 and 87. Factors of 14 The Factors of 14 are the numbers that you can evenly divide into 14. Thus, the Factors of 14 are 1, 2, 7, and 14. Factors of 47 The Factors of 47 are the numbers that you can evenly divide into 47. Thus, the Factors of 47 are 1 and 47. Factors of 87 Web(c)8x 6 (mod 14) Answer. Since gcd(8;14) = 2 and 2j6, there are 2 answers. First, 813 = 14 8( 1) 14 6, so one solution is x = 13 . Then the other solution is x = 13 14=2 = 6 : (d)66x 100 (mod 121) Answer. Since gcd(66;121) = 11 and 11 - 100, there are no solutions. (e)21x 14 (mod 91) Answer. Since gcd(21;91) = 7 and 7 j14, there are 7 solutions. jody long yarn facebook